Sagot :
Solution:
[tex]\text{number of Hg atoms = 150 g Hg} × \frac{\text{1 mol Hg}}{\text{200.6 g Hg}} × \frac{\text{6.022 × 10²³ Hg atoms}}{\text{1 mol Hg}}[/tex]
[tex]\boxed{\text{number of Hg atoms = 4.50 × 10²³ atoms}}[/tex]
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Solution:
[tex]\text{number of Hg atoms = 150 g Hg} × \frac{\text{1 mol Hg}}{\text{200.6 g Hg}} × \frac{\text{6.022 × 10²³ Hg atoms}}{\text{1 mol Hg}}[/tex]
[tex]\boxed{\text{number of Hg atoms = 4.50 × 10²³ atoms}}[/tex]
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