Answer and solutions
(m, n) = (2, 1) gives the triple (3, 4, 5), while (m, n) = (5,2) gives the triple (21, 20 ... 7 is satisfied by (lxi, Iyl)] = (3,1), (13,9), (75,53), and these yield the triples (-3 ... 2. 1.1. For 1, (x, y, m, n) = (3,1,1,1), and for 36, (x, y, m, n) = (17,6,6,8). ... 2(u + 1). 4.7(e). Since x2 = dy2 + k, the smallest value of Ixl among solutions occurs along.
